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804387a1af
Architechtures normally don't need to set a HARDIRQ_BITS unless they have hardcoded a specific value in assembly. This drops the definition from asm-generic/hardirq.h, which results in linux/hardirq.h setting its default of 10. Both the old default of 8 and the linux/hardirq.h default of 10 are sufficient because they only limit the number of nested hardirqs, and we normally run out of stack space much earlier than exceeding 256 or even 1024 nested interrupts. Reported-by: Mike Frysinger <vapier@gentoo.org> Acked-by: Steven Rostedt <rostedt@goodmis.org> Signed-off-by: Arnd Bergmann <arnd@arndb.de>
21 lines
494 B
C
21 lines
494 B
C
#ifndef __ASM_GENERIC_HARDIRQ_H
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#define __ASM_GENERIC_HARDIRQ_H
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#include <linux/cache.h>
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#include <linux/threads.h>
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#include <linux/irq.h>
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typedef struct {
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unsigned long __softirq_pending;
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} ____cacheline_aligned irq_cpustat_t;
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#include <linux/irq_cpustat.h> /* Standard mappings for irq_cpustat_t above */
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#ifndef ack_bad_irq
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static inline void ack_bad_irq(unsigned int irq)
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{
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printk(KERN_CRIT "unexpected IRQ trap at vector %02x\n", irq);
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}
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#endif
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#endif /* __ASM_GENERIC_HARDIRQ_H */
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