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generic swap(): don't return a value from swap()

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The swap() macro is accidentally retuning the value of its first argument.
Change it into a doesn't-return-anything macro before someone goes and
relies upon this behaviour.

Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl>
Cc: Wu Fengguang <wfg@linux.intel.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Peter Zijlstra 2009-02-04 15:11:59 -08:00 committed by Linus Torvalds
parent c073b2db00
commit ac7b900490
1 changed files with 2 additions and 1 deletions
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3
include/linux/kernel.h
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@ -480,7 +480,8 @@ static inline char *pack_hex_byte(char *buf, u8 byte)
/* /*
* swap - swap value of @a and @b * swap - swap value of @a and @b
*/ */
#define swap(a, b) ({ typeof(a) __tmp = (a); (a) = (b); (b) = __tmp; }) #define swap(a, b) \
do { typeof(a) __tmp = (a); (a) = (b); (b) = __tmp; } while (0)
/** /**
* container_of - cast a member of a structure out to the containing structure * container_of - cast a member of a structure out to the containing structure