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[PATCH] Fix multiple conversion bugs in msecs_to_jiffies

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Fix multiple conversion bugs in msecs_to_jiffies().

The main problem is that this condition:

	if (m > jiffies_to_msecs(MAX_JIFFY_OFFSET))

overflows if HZ is smaller than 1000!

This change is user-visible: for HZ=250 SUS-compliant poll()-timeout
value of -20 is mistakenly converted to 'immediate timeout'.

(The new dyntick code also triggered this, that's how we noticed.)

Signed-off-by: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
Cc: john stultz <johnstul@us.ibm.com>
Cc: Roman Zippel <zippel@linux-m68k.org>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Ingo Molnar 2007-02-16 01:27:28 -08:00 committed by Linus Torvalds
parent 8b9365d753
commit 41cf54455d
1 changed files with 42 additions and 1 deletions
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43
kernel/time.c
View file

@ -500,15 +500,56 @@ unsigned int jiffies_to_usecs(const unsigned long j)
}
EXPORT_SYMBOL(jiffies_to_usecs);
/*
* When we convert to jiffies then we interpret incoming values
* the following way:
*
* - negative values mean 'infinite timeout' (MAX_JIFFY_OFFSET)
*
* - 'too large' values [that would result in larger than
* MAX_JIFFY_OFFSET values] mean 'infinite timeout' too.
*
* - all other values are converted to jiffies by either multiplying
* the input value by a factor or dividing it with a factor
*
* We must also be careful about 32-bit overflows.
*/
unsigned long msecs_to_jiffies(const unsigned int m)
{
if (m > jiffies_to_msecs(MAX_JIFFY_OFFSET))
/*
* Negative value, means infinite timeout:
*/
if ((int)m < 0)
return MAX_JIFFY_OFFSET;
#if HZ <= MSEC_PER_SEC && !(MSEC_PER_SEC % HZ)
/*
* HZ is equal to or smaller than 1000, and 1000 is a nice
* round multiple of HZ, divide with the factor between them,
* but round upwards:
*/
return (m + (MSEC_PER_SEC / HZ) - 1) / (MSEC_PER_SEC / HZ);
#elif HZ > MSEC_PER_SEC && !(HZ % MSEC_PER_SEC)
/*
* HZ is larger than 1000, and HZ is a nice round multiple of
* 1000 - simply multiply with the factor between them.
*
* But first make sure the multiplication result cannot
* overflow:
*/
if (m > jiffies_to_msecs(MAX_JIFFY_OFFSET))
return MAX_JIFFY_OFFSET;
return m * (HZ / MSEC_PER_SEC);
#else
/*
* Generic case - multiply, round and divide. But first
* check that if we are doing a net multiplication, that
* we wouldnt overflow:
*/
if (HZ > MSEC_PER_SEC && m > jiffies_to_msecs(MAX_JIFFY_OFFSET))
return MAX_JIFFY_OFFSET;
return (m * HZ + MSEC_PER_SEC - 1) / MSEC_PER_SEC;
#endif
}