vsprintf: fix io/mem resource width

The leading "0x" consumes field width, so leave space for it in addition to
the 4 or 8 hex digits.  This means we'll print "0x0000-0x01df" rather than
"0x00-0x1df", for example.

Signed-off-by: Bjorn Helgaas <bjorn.helgaas@hp.com>
Signed-off-by: Jesse Barnes <jbarnes@virtuousgeek.org>
This commit is contained in:
Bjorn Helgaas 2009-10-06 15:33:29 -06:00 committed by Jesse Barnes
parent 3368dd2958
commit 2840537228

View file

@ -598,11 +598,11 @@ static char *resource_string(char *buf, char *end, struct resource *res,
struct printf_spec spec)
{
#ifndef IO_RSRC_PRINTK_SIZE
#define IO_RSRC_PRINTK_SIZE 4
#define IO_RSRC_PRINTK_SIZE 6
#endif
#ifndef MEM_RSRC_PRINTK_SIZE
#define MEM_RSRC_PRINTK_SIZE 8
#define MEM_RSRC_PRINTK_SIZE 10
#endif
struct printf_spec num_spec = {
.base = 16,