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[PATCH] Better PLL frequency matching for tdfxfb driver

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Improve the PLL frequency matching in the tdfxfb driver.  Instead of
requiring 64260 iterations to obtain the closest supported PLL frequency,
this code does it with the same degree of accuracy in at most 768
iterations.

Signed-off-by: Richard Drummond <evilrich@rcdrummond.net>
Cc: <linux-fbdev-devel@lists.sourceforge.net>
Signed-off-by: Andrew Morton <akpm@osdl.org>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>
This commit is contained in:
Richard Drummond 2005-05-01 08:59:24 -07:00 committed by Linus Torvalds
parent 7c2f891cb6
commit 0fbe9cafff
1 changed files with 31 additions and 12 deletions
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43
drivers/video/tdfxfb.c
View file

@ -317,30 +317,49 @@ static inline void do_setpalentry(struct tdfx_par *par, unsigned regno, u32 c)
static u32 do_calc_pll(int freq, int* freq_out)
{
int m, n, k, best_m, best_n, best_k, f_cur, best_error;
int m, n, k, best_m, best_n, best_k, best_error;
int fref = 14318;
/* this really could be done with more intelligence --
255*63*4 = 64260 iterations is silly */
best_error = freq;
best_n = best_m = best_k = 0;
for (n = 1; n < 256; n++) {
for (m = 1; m < 64; m++) {
for (k = 0; k < 4; k++) {
f_cur = fref*(n + 2)/(m + 2)/(1 << k);
if (abs(f_cur - freq) < best_error) {
best_error = abs(f_cur-freq);
best_n = n;
best_m = m;
best_k = k;
for (k = 3; k >= 0; k--) {
for (m = 63; m >= 0; m--) {
/*
* Estimate value of n that produces target frequency
* with current m and k
*/
int n_estimated = (freq * (m + 2) * (1 << k) / fref) - 2;
/* Search neighborhood of estimated n */
for (n = max(0, n_estimated - 1);
n <= min(255, n_estimated + 1); n++) {
/*
* Calculate PLL freqency with current m, k and
* estimated n
*/
int f = fref * (n + 2) / (m + 2) / (1 << k);
int error = abs (f - freq);
/*
* If this is the closest we've come to the
* target frequency then remember n, m and k
*/
if (error < best_error) {
best_error = error;
best_n = n;
best_m = m;
best_k = k;
}
}
}
}
n = best_n;
m = best_m;
k = best_k;
*freq_out = fref*(n + 2)/(m + 2)/(1 << k);
return (n << 8) | (m << 2) | k;
}